3(z-2)=4z+1

Solution for 3(z-2)=4z+1 equation:

Simplifying
3(z + -2) = 4z + 1

Reorder the terms:
3(-2 + z) = 4z + 1
(-2 * 3 + z * 3) = 4z + 1
(-6 + 3z) = 4z + 1

Reorder the terms:
-6 + 3z = 1 + 4z

Solving
-6 + 3z = 1 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-6 + 3z + -4z = 1 + 4z + -4z

Combine like terms: 3z + -4z = -1z
-6 + -1z = 1 + 4z + -4z

Combine like terms: 4z + -4z = 0
-6 + -1z = 1 + 0
-6 + -1z = 1

Add '6' to each side of the equation.
-6 + 6 + -1z = 1 + 6

Combine like terms: -6 + 6 = 0
0 + -1z = 1 + 6
-1z = 1 + 6

Combine like terms: 1 + 6 = 7
-1z = 7

Divide each side by '-1'.
z = -7

Simplifying
z = -7