3(z-2)=7z+11

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Solution for 3(z-2)=7z+11 equation: 



3(z-2)=7z+11

We move all terms to the left:

3(z-2)-(7z+11)=0

We multiply parentheses

3z-(7z+11)-6=0

We get rid of parentheses

3z-7z-11-6=0

We add all the numbers together, and all the variables

-4z-17=0

We move all terms containing z to the left, all other terms to the right

-4z=17

z=17/-4

z=-4+1/4

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