3(z-2-z+1)=3z-3

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Solution for 3(z-2-z+1)=3z-3 equation: 



3(z-2-z+1)=3z-3

We move all terms to the left:

3(z-2-z+1)-(3z-3)=0

We add all the numbers together, and all the variables

-(3z-3)+3(-1)=0

We add all the numbers together, and all the variables

-(3z-3)-3=0

We get rid of parentheses

-3z+3-3=0

We add all the numbers together, and all the variables

-3z=0

z=0/-3

z=0

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