3(z-21)+2(z-2)=13

Solution for 3(z-21)+2(z-2)=13 equation:

Simplifying
3(z + -21) + 2(z + -2) = 13

Reorder the terms:
3(-21 + z) + 2(z + -2) = 13
(-21 * 3 + z * 3) + 2(z + -2) = 13
(-63 + 3z) + 2(z + -2) = 13

Reorder the terms:
-63 + 3z + 2(-2 + z) = 13
-63 + 3z + (-2 * 2 + z * 2) = 13
-63 + 3z + (-4 + 2z) = 13

Reorder the terms:
-63 + -4 + 3z + 2z = 13

Combine like terms: -63 + -4 = -67
-67 + 3z + 2z = 13

Combine like terms: 3z + 2z = 5z
-67 + 5z = 13

Solving
-67 + 5z = 13

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '67' to each side of the equation.
-67 + 67 + 5z = 13 + 67

Combine like terms: -67 + 67 = 0
0 + 5z = 13 + 67
5z = 13 + 67

Combine like terms: 13 + 67 = 80
5z = 80

Divide each side by '5'.
z = 16

Simplifying
z = 16