3(z-24)+2(z-4)=15

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Solution for 3(z-24)+2(z-4)=15 equation: 



3(z-24)+2(z-4)=15

We move all terms to the left:

3(z-24)+2(z-4)-(15)=0

We multiply parentheses

3z+2z-72-8-15=0

We add all the numbers together, and all the variables

5z-95=0

We move all terms containing z to the left, all other terms to the right

5z=95

z=95/5

z=19

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