3(z-3)-1=4(z-4)

Solution for 3(z-3)-1=4(z-4) equation:

3(z-3)-1=4(z-4)

We move all terms to the left:

3(z-3)-1-(4(z-4))=0

We multiply parentheses

3z-(4(z-4))-9-1=0


We calculate terms in parentheses: -(4(z-4)), so:

4(z-4)

We multiply parentheses

4z-16

Back to the equation:

-(4z-16)


We add all the numbers together, and all the variables

3z-(4z-16)-10=0

We get rid of parentheses

3z-4z+16-10=0

We add all the numbers together, and all the variables

-1z+6=0

We move all terms containing z to the left, all other terms to the right

-z=-6

z=-6/-1

z=+6