3(z-3)=5(2z+0)

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Solution for 3(z-3)=5(2z+0) equation: 



3(z-3)=5(2z+0)

We move all terms to the left:

3(z-3)-(5(2z+0))=0

We add all the numbers together, and all the variables

3(z-3)-(5(+2z))=0

We multiply parentheses

3z-(5(+2z))-9=0



We calculate terms in parentheses: -(5(+2z)), so:

5(+2z)

We multiply parentheses

10z

Back to the equation:

-(10z)



We add all the numbers together, and all the variables

-7z-9=0

We move all terms containing z to the left, all other terms to the right

-7z=9

z=9/-7

z=-1+2/7

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