3(z-4)+4z-2=

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Solution for 3(z-4)+4z-2= equation:


3(z-4)+4z-2=0

We simplify the equation to the form, which is simple to understand 
3(z-4)+4z-2=0

Reorder the terms in parentheses
+(+3z-12)+4z-2=0

Remove unnecessary parentheses
+3z-12+4z-2=0

We move all terms containing z to the left and all other terms to the right. 
+3z+4z=0+12+2

We simplify left and right side of the equation. 
+7z=+14

We divide both sides of the equation by 7 to get z. 
z=2

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