3(z-4)-5=-2z+5z-9

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Solution for 3(z-4)-5=-2z+5z-9 equation: 


Simplifying
3(z + -4) + -5 = -2z + 5z + -9

Reorder the terms:
3(-4 + z) + -5 = -2z + 5z + -9
(-4 * 3 + z * 3) + -5 = -2z + 5z + -9
(-12 + 3z) + -5 = -2z + 5z + -9

Reorder the terms:
-12 + -5 + 3z = -2z + 5z + -9

Combine like terms: -12 + -5 = -17
-17 + 3z = -2z + 5z + -9

Reorder the terms:
-17 + 3z = -9 + -2z + 5z

Combine like terms: -2z + 5z = 3z
-17 + 3z = -9 + 3z

Add '-3z' to each side of the equation.
-17 + 3z + -3z = -9 + 3z + -3z

Combine like terms: 3z + -3z = 0
-17 + 0 = -9 + 3z + -3z
-17 = -9 + 3z + -3z

Combine like terms: 3z + -3z = 0
-17 = -9 + 0
-17 = -9

Solving
-17 = -9

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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