3(z-4)-z=2(z-6)

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Solution for 3(z-4)-z=2(z-6) equation:


Simplifying
3(z + -4) + -1z = 2(z + -6)

Reorder the terms:
3(-4 + z) + -1z = 2(z + -6)
(-4 * 3 + z * 3) + -1z = 2(z + -6)
(-12 + 3z) + -1z = 2(z + -6)

Combine like terms: 3z + -1z = 2z
-12 + 2z = 2(z + -6)

Reorder the terms:
-12 + 2z = 2(-6 + z)
-12 + 2z = (-6 * 2 + z * 2)
-12 + 2z = (-12 + 2z)

Add '12' to each side of the equation.
-12 + 12 + 2z = -12 + 12 + 2z

Combine like terms: -12 + 12 = 0
0 + 2z = -12 + 12 + 2z
2z = -12 + 12 + 2z

Combine like terms: -12 + 12 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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