3(z-4)2=27

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Solution for 3(z-4)2=27 equation: 



3(z-4)2=27

We move all terms to the left:

3(z-4)2-(27)=0

We multiply parentheses

6z-24-27=0

We add all the numbers together, and all the variables

6z-51=0

We move all terms containing z to the left, all other terms to the right

6z=51

z=51/6

z=8+1/2

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