3(z-4)=2(2+4)

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Solution for 3(z-4)=2(2+4) equation: 



3(z-4)=2(2+4)

We move all terms to the left:

3(z-4)-(2(2+4))=0

We add all the numbers together, and all the variables

3(z-4)-(26)=0

We add all the numbers together, and all the variables

3(z-4)-26=0

We multiply parentheses

3z-12-26=0

We add all the numbers together, and all the variables

3z-38=0

We move all terms containing z to the left, all other terms to the right

3z=38

z=38/3

z=12+2/3

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