3(z-4)=2(3-z)

Solution for 3(z-4)=2(3-z) equation:

3(z-4)=2(3-z)

We move all terms to the left:

3(z-4)-(2(3-z))=0

We add all the numbers together, and all the variables

3(z-4)-(2(-1z+3))=0

We multiply parentheses

3z-(2(-1z+3))-12=0


We calculate terms in parentheses: -(2(-1z+3)), so:

2(-1z+3)

We multiply parentheses

-2z+6

Back to the equation:

-(-2z+6)


We get rid of parentheses

3z+2z-6-12=0

We add all the numbers together, and all the variables

5z-18=0

We move all terms containing z to the left, all other terms to the right

5z=18

z=18/5

z=3+3/5