3(z-4)=4(2z+3)

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Solution for 3(z-4)=4(2z+3) equation: 



3(z-4)=4(2z+3)

We move all terms to the left:

3(z-4)-(4(2z+3))=0

We multiply parentheses

3z-(4(2z+3))-12=0



We calculate terms in parentheses: -(4(2z+3)), so:

4(2z+3)

We multiply parentheses

8z+12

Back to the equation:

-(8z+12)



We get rid of parentheses

3z-8z-12-12=0

We add all the numbers together, and all the variables

-5z-24=0

We move all terms containing z to the left, all other terms to the right

-5z=24

z=24/-5

z=-4+4/5

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