3(z-4)=4(3-z)

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Solution for 3(z-4)=4(3-z) equation: 



3(z-4)=4(3-z)

We move all terms to the left:

3(z-4)-(4(3-z))=0

We add all the numbers together, and all the variables

3(z-4)-(4(-1z+3))=0

We multiply parentheses

3z-(4(-1z+3))-12=0



We calculate terms in parentheses: -(4(-1z+3)), so:

4(-1z+3)

We multiply parentheses

-4z+12

Back to the equation:

-(-4z+12)



We get rid of parentheses

3z+4z-12-12=0

We add all the numbers together, and all the variables

7z-24=0

We move all terms containing z to the left, all other terms to the right

7z=24

z=24/7

z=3+3/7

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