3(z-4)=5(z+8)

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Solution for 3(z-4)=5(z+8) equation: 



3(z-4)=5(z+8)

We move all terms to the left:

3(z-4)-(5(z+8))=0

We multiply parentheses

3z-(5(z+8))-12=0



We calculate terms in parentheses: -(5(z+8)), so:

5(z+8)

We multiply parentheses

5z+40

Back to the equation:

-(5z+40)



We get rid of parentheses

3z-5z-40-12=0

We add all the numbers together, and all the variables

-2z-52=0

We move all terms containing z to the left, all other terms to the right

-2z=52

z=52/-2

z=-26

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