3(z-4)=6z-12-3z

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Solution for 3(z-4)=6z-12-3z equation: 



3(z-4)=6z-12-3z

We move all terms to the left:

3(z-4)-(6z-12-3z)=0

We add all the numbers together, and all the variables

3(z-4)-(3z-12)=0

We multiply parentheses

3z-(3z-12)-12=0

We get rid of parentheses

3z-3z+12-12=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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