3(z-4)=7z

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Solution for 3(z-4)=7z equation: 



3(z-4)=7z

We move all terms to the left:

3(z-4)-(7z)=0

We add all the numbers together, and all the variables

-7z+3(z-4)=0

We multiply parentheses

-7z+3z-12=0

We add all the numbers together, and all the variables

-4z-12=0

We move all terms containing z to the left, all other terms to the right

-4z=12

z=12/-4

z=-3

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