3(z-4)=7z

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Solution for 3(z-4)=7z equation:



3(z-4)=7z
We move all terms to the left:
3(z-4)-(7z)=0
We add all the numbers together, and all the variables
-7z+3(z-4)=0
We multiply parentheses
-7z+3z-12=0
We add all the numbers together, and all the variables
-4z-12=0
We move all terms containing z to the left, all other terms to the right
-4z=12
z=12/-4
z=-3

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