3(z-42)=99

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Solution for 3(z-42)=99 equation: 



3(z-42)=99

We move all terms to the left:

3(z-42)-(99)=0

We multiply parentheses

3z-126-99=0

We add all the numbers together, and all the variables

3z-225=0

We move all terms containing z to the left, all other terms to the right

3z=225

z=225/3

z=75

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