3(z-5)=15

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Solution for 3(z-5)=15 equation: 



3(z-5)=15

We move all terms to the left:

3(z-5)-(15)=0

We multiply parentheses

3z-15-15=0

We add all the numbers together, and all the variables

3z-30=0

We move all terms containing z to the left, all other terms to the right

3z=30

z=30/3

z=10

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