3(z-5)=2z+13

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Solution for 3(z-5)=2z+13 equation:


Simplifying
3(z + -5) = 2z + 13

Reorder the terms:
3(-5 + z) = 2z + 13
(-5 * 3 + z * 3) = 2z + 13
(-15 + 3z) = 2z + 13

Reorder the terms:
-15 + 3z = 13 + 2z

Solving
-15 + 3z = 13 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-15 + 3z + -2z = 13 + 2z + -2z

Combine like terms: 3z + -2z = 1z
-15 + 1z = 13 + 2z + -2z

Combine like terms: 2z + -2z = 0
-15 + 1z = 13 + 0
-15 + 1z = 13

Add '15' to each side of the equation.
-15 + 15 + 1z = 13 + 15

Combine like terms: -15 + 15 = 0
0 + 1z = 13 + 15
1z = 13 + 15

Combine like terms: 13 + 15 = 28
1z = 28

Divide each side by '1'.
z = 28

Simplifying
z = 28

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