3(z-5)=4z+11

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Solution for 3(z-5)=4z+11 equation: 



3(z-5)=4z+11

We move all terms to the left:

3(z-5)-(4z+11)=0

We multiply parentheses

3z-(4z+11)-15=0

We get rid of parentheses

3z-4z-11-15=0

We add all the numbers together, and all the variables

-1z-26=0

We move all terms containing z to the left, all other terms to the right

-z=26

z=26/-1

z=-26

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