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3(z-5)=5(z+4)
We move all terms to the left:
3(z-5)-(5(z+4))=0
We multiply parentheses
3z-(5(z+4))-15=0
We calculate terms in parentheses: -(5(z+4)), so:We get rid of parentheses
5(z+4)
We multiply parentheses
5z+20
Back to the equation:
-(5z+20)
3z-5z-20-15=0
We add all the numbers together, and all the variables
-2z-35=0
We move all terms containing z to the left, all other terms to the right
-2z=35
z=35/-2
z=-17+1/2
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