3)4(y-2)+6y=7(y-8)-3(10-y)

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Solution for 3)4(y-2)+6y=7(y-8)-3(10-y) equation: 



3)4(y-2)+6y=7(y-8)-3(10-y)

We move all terms to the left:

3)4(y-2)+6y-(7(y-8)-3(10-y))=0

We add all the numbers together, and all the variables

3)4(y-2)+6y-(7(y-8)-3(-1y+10))=0

We multiply parentheses

3)4(y-2)+6y-(7(y-8)+3y-=0

We add all the numbers together, and all the variables

3y+3)4(y-2)+6y-(7(y-8)=0

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