3)7(y-4)+y=2(6+4y)

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Solution for 3)7(y-4)+y=2(6+4y) equation: 



3)7(y-4)+y=2(6+4y)

We move all terms to the left:

3)7(y-4)+y-(2(6+4y))=0

We add all the numbers together, and all the variables

3)7(y-4)+y-(2(4y+6))=0

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