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3(1/3x-12)=7x+6
We move all terms to the left:
3(1/3x-12)-(7x+6)=0
Domain of the equation: 3x-12)!=0We multiply parentheses
x∈R
3x-(7x+6)-36=0
We get rid of parentheses
3x-7x-6-36=0
We add all the numbers together, and all the variables
-4x-42=0
We move all terms containing x to the left, all other terms to the right
-4x=42
x=42/-4
x=-10+1/2
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