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3(1/4*5x+5)=18+x
We move all terms to the left:
3(1/4*5x+5)-(18+x)=0
Domain of the equation: 4*5x+5)!=0We add all the numbers together, and all the variables
x∈R
3(1/4*5x+5)-(x+18)=0
We multiply parentheses
15x^2-(x+18)+15=0
We get rid of parentheses
15x^2-x-18+15=0
We add all the numbers together, and all the variables
15x^2-1x-3=0
a = 15; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·15·(-3)
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{181}}{2*15}=\frac{1-\sqrt{181}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{181}}{2*15}=\frac{1+\sqrt{181}}{30} $
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