3*(2+5x)/4=2*(6x-3)/5

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Solution for 3*(2+5x)/4=2*(6x-3)/5 equation: 



3(2+5x)/4=2(6x-3)/5

We move all terms to the left:

3(2+5x)/4-(2(6x-3)/5)=0

We add all the numbers together, and all the variables

3(5x+2)/4-(2(6x-3)/5)=0

We calculate fractions


15x/()+(-(2(6x-3)*4)/()=0



We calculate terms in parentheses: +(-(2(6x-3)*4)/(), so:

-(2(6x-3)*4)/(

We multiply all the terms by the denominator


-(2(6x-3)*4)



We calculate terms in parentheses: -(2(6x-3)*4), so:

2(6x-3)*4

We multiply parentheses

48x-24

Back to the equation:

-(48x-24)



We get rid of parentheses

-48x+24

Back to the equation:

+(-48x+24)



We get rid of parentheses

15x/()-48x+24=0

We multiply all the terms by the denominator


15x-48x*()+24*()=0

We add all the numbers together, and all the variables

15x-48x*()=0

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