3*(2k-5)+2=-(12k-23)

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Solution for 3*(2k-5)+2=-(12k-23) equation: 



3(2k-5)+2=-(12k-23)

We move all terms to the left:

3(2k-5)+2-(-(12k-23))=0

We multiply parentheses

6k-(-(12k-23))-15+2=0



We calculate terms in parentheses: -(-(12k-23)), so:

-(12k-23)

We get rid of parentheses

-12k+23

Back to the equation:

-(-12k+23)



We add all the numbers together, and all the variables

6k-(-12k+23)-13=0

We get rid of parentheses

6k+12k-23-13=0

We add all the numbers together, and all the variables

18k-36=0

We move all terms containing k to the left, all other terms to the right

18k=36

k=36/18

k=2

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