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3(2x-1)-2(1-x)=5+(x-3)
We move all terms to the left:
3(2x-1)-2(1-x)-(5+(x-3))=0
We add all the numbers together, and all the variables
3(2x-1)-2(-1x+1)-(5+(x-3))=0
We multiply parentheses
6x+2x-(5+(x-3))-3-2=0
We calculate terms in parentheses: -(5+(x-3)), so:We add all the numbers together, and all the variables
5+(x-3)
determiningTheFunctionDomain (x-3)+5
We get rid of parentheses
x-3+5
We add all the numbers together, and all the variables
x+2
Back to the equation:
-(x+2)
8x-(x+2)-5=0
We get rid of parentheses
8x-x-2-5=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1
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