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3(2x-5)+6=5(3-5x)+6x=
We move all terms to the left:
3(2x-5)+6-(5(3-5x)+6x)=0
We add all the numbers together, and all the variables
3(2x-5)-(5(-5x+3)+6x)+6=0
We multiply parentheses
6x-(5(-5x+3)+6x)-15+6=0
We calculate terms in parentheses: -(5(-5x+3)+6x), so:We add all the numbers together, and all the variables
5(-5x+3)+6x
We add all the numbers together, and all the variables
6x+5(-5x+3)
We multiply parentheses
6x-25x+15
We add all the numbers together, and all the variables
-19x+15
Back to the equation:
-(-19x+15)
6x-(-19x+15)-9=0
We get rid of parentheses
6x+19x-15-9=0
We add all the numbers together, and all the variables
25x-24=0
We move all terms containing x to the left, all other terms to the right
25x=24
x=24/25
x=24/25
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