3*(2y-1)=5*(3y+2)

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Solution for 3*(2y-1)=5*(3y+2) equation: 



3(2y-1)=5(3y+2)

We move all terms to the left:

3(2y-1)-(5(3y+2))=0

We multiply parentheses

6y-(5(3y+2))-3=0



We calculate terms in parentheses: -(5(3y+2)), so:

5(3y+2)

We multiply parentheses

15y+10

Back to the equation:

-(15y+10)



We get rid of parentheses

6y-15y-10-3=0

We add all the numbers together, and all the variables

-9y-13=0

We move all terms containing y to the left, all other terms to the right

-9y=13

y=13/-9

y=-1+4/9

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