3*(3-x)+9=2*(x-4)+6

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Solution for 3*(3-x)+9=2*(x-4)+6 equation: 



3(3-x)+9=2(x-4)+6

We move all terms to the left:

3(3-x)+9-(2(x-4)+6)=0

We add all the numbers together, and all the variables

3(-1x+3)-(2(x-4)+6)+9=0

We multiply parentheses

-3x-(2(x-4)+6)+9+9=0



We calculate terms in parentheses: -(2(x-4)+6), so:

2(x-4)+6

We multiply parentheses

2x-8+6

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

-3x-(2x-2)+18=0

We get rid of parentheses

-3x-2x+2+18=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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