3*(3a-1)-3a=-3*(1-2a)

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Solution for 3*(3a-1)-3a=-3*(1-2a) equation: 



3*(3a-1)-3a=-3*(1-2a)

We move all terms to the left:

3*(3a-1)-3a-(-3*(1-2a))=0

We add all the numbers together, and all the variables

3*(3a-1)-3a-(-3*(-2a+1))=0

We add all the numbers together, and all the variables

-3a+3*(3a-1)-(-3*(-2a+1))=0

We multiply parentheses

-3a+9a-(-3*(-2a+1))-3=0



We calculate terms in parentheses: -(-3*(-2a+1)), so:

-3*(-2a+1)

We multiply parentheses

6a-3

Back to the equation:

-(6a-3)



We add all the numbers together, and all the variables

6a-(6a-3)-3=0

We get rid of parentheses

6a-6a+3-3=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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