3*(4x+3)-5=1-6*(1-x)

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Solution for 3*(4x+3)-5=1-6*(1-x) equation: 



3(4x+3)-5=1-6(1-x)

We move all terms to the left:

3(4x+3)-5-(1-6(1-x))=0

We add all the numbers together, and all the variables

3(4x+3)-(1-6(-1x+1))-5=0

We multiply parentheses

12x-(1-6(-1x+1))+9-5=0



We calculate terms in parentheses: -(1-6(-1x+1)), so:

1-6(-1x+1)

determiningTheFunctionDomain
-6(-1x+1)+1

We multiply parentheses

6x-6+1

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)



We add all the numbers together, and all the variables

12x-(6x-5)+4=0

We get rid of parentheses

12x-6x+5+4=0

We add all the numbers together, and all the variables

6x+9=0

We move all terms containing x to the left, all other terms to the right

6x=-9

x=-9/6

x=-1+1/2

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