3*(5t+1)=t+4+t-2

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Solution for 3*(5t+1)=t+4+t-2 equation: 



3(5t+1)=t+4+t-2

We move all terms to the left:

3(5t+1)-(t+4+t-2)=0

We add all the numbers together, and all the variables

3(5t+1)-(2t+2)=0

We multiply parentheses

15t-(2t+2)+3=0

We get rid of parentheses

15t-2t-2+3=0

We add all the numbers together, and all the variables

13t+1=0

We move all terms containing t to the left, all other terms to the right

13t=-1

t=-1/13

t=-1/13

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