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3(6v+4)=9(2v-3)
We move all terms to the left:
3(6v+4)-(9(2v-3))=0
We multiply parentheses
18v-(9(2v-3))+12=0
We calculate terms in parentheses: -(9(2v-3)), so:We get rid of parentheses
9(2v-3)
We multiply parentheses
18v-27
Back to the equation:
-(18v-27)
18v-18v+27+12=0
We add all the numbers together, and all the variables
39!=0
There is no solution for this equation
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