3*(a-4)+3*(4-a)+2a-1=3

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Solution for 3*(a-4)+3*(4-a)+2a-1=3 equation: 



3(a-4)+3(4-a)+2a-1=3

We move all terms to the left:

3(a-4)+3(4-a)+2a-1-(3)=0

We add all the numbers together, and all the variables

3(a-4)+3(-1a+4)+2a-1-3=0

We add all the numbers together, and all the variables

2a+3(a-4)+3(-1a+4)-4=0

We multiply parentheses

2a+3a-3a-12+12-4=0

We add all the numbers together, and all the variables

2a-4=0

We move all terms containing a to the left, all other terms to the right

2a=4

a=4/2

a=2

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