3*(x+2)+4*(x-3)=17

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Solution for 3*(x+2)+4*(x-3)=17 equation: 



3(x+2)+4(x-3)=17

We move all terms to the left:

3(x+2)+4(x-3)-(17)=0

We multiply parentheses

3x+4x+6-12-17=0

We add all the numbers together, and all the variables

7x-23=0

We move all terms containing x to the left, all other terms to the right

7x=23

x=23/7

x=3+2/7

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