3*(x+2)=10+2*(5-2x)

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Solution for 3*(x+2)=10+2*(5-2x) equation: 



3(x+2)=10+2(5-2x)

We move all terms to the left:

3(x+2)-(10+2(5-2x))=0

We add all the numbers together, and all the variables

3(x+2)-(10+2(-2x+5))=0

We multiply parentheses

3x-(10+2(-2x+5))+6=0



We calculate terms in parentheses: -(10+2(-2x+5)), so:

10+2(-2x+5)

determiningTheFunctionDomain
2(-2x+5)+10

We multiply parentheses

-4x+10+10

We add all the numbers together, and all the variables

-4x+20

Back to the equation:

-(-4x+20)



We get rid of parentheses

3x+4x-20+6=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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