3*(x+5)=4-2*(2-x)

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Solution for 3*(x+5)=4-2*(2-x) equation: 



3(x+5)=4-2(2-x)

We move all terms to the left:

3(x+5)-(4-2(2-x))=0

We add all the numbers together, and all the variables

3(x+5)-(4-2(-1x+2))=0

We multiply parentheses

3x-(4-2(-1x+2))+15=0



We calculate terms in parentheses: -(4-2(-1x+2)), so:

4-2(-1x+2)

determiningTheFunctionDomain
-2(-1x+2)+4

We multiply parentheses

2x-4+4

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

x+15=0

We move all terms containing x to the left, all other terms to the right

x=-15

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