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3(x-2)+1=x+2(x+2)
We move all terms to the left:
3(x-2)+1-(x+2(x+2))=0
We multiply parentheses
3x-(x+2(x+2))-6+1=0
We calculate terms in parentheses: -(x+2(x+2)), so:We add all the numbers together, and all the variables
x+2(x+2)
We multiply parentheses
x+2x+4
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
3x-(3x+4)-5=0
We get rid of parentheses
3x-3x-4-5=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation
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