3*(x-2)+2*(x+1)=x+48

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Solution for 3*(x-2)+2*(x+1)=x+48 equation: 



3(x-2)+2(x+1)=x+48

We move all terms to the left:

3(x-2)+2(x+1)-(x+48)=0

We multiply parentheses

3x+2x-(x+48)-6+2=0

We get rid of parentheses

3x+2x-x-48-6+2=0

We add all the numbers together, and all the variables

4x-52=0

We move all terms containing x to the left, all other terms to the right

4x=52

x=52/4

x=13

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