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3*(x-6)=2x(x-7)
We move all terms to the left:
3*(x-6)-(2x(x-7))=0
We multiply parentheses
3x-(2x(x-7))-18=0
We calculate terms in parentheses: -(2x(x-7)), so:We get rid of parentheses
2x(x-7)
We multiply parentheses
2x^2-14x
Back to the equation:
-(2x^2-14x)
-2x^2+3x+14x-18=0
We add all the numbers together, and all the variables
-2x^2+17x-18=0
a = -2; b = 17; c = -18;
Δ = b2-4ac
Δ = 172-4·(-2)·(-18)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{145}}{2*-2}=\frac{-17-\sqrt{145}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{145}}{2*-2}=\frac{-17+\sqrt{145}}{-4} $
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