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3(x-7)+2=9(2-x)+51
We move all terms to the left:
3(x-7)+2-(9(2-x)+51)=0
We add all the numbers together, and all the variables
3(x-7)-(9(-1x+2)+51)+2=0
We multiply parentheses
3x-(9(-1x+2)+51)-21+2=0
We calculate terms in parentheses: -(9(-1x+2)+51), so:We add all the numbers together, and all the variables
9(-1x+2)+51
We multiply parentheses
-9x+18+51
We add all the numbers together, and all the variables
-9x+69
Back to the equation:
-(-9x+69)
3x-(-9x+69)-19=0
We get rid of parentheses
3x+9x-69-19=0
We add all the numbers together, and all the variables
12x-88=0
We move all terms containing x to the left, all other terms to the right
12x=88
x=88/12
x=7+1/3
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