3*2-2*3+u=(3*3-3*8)(2)+u

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Solution for 3*2-2*3+u=(3*3-3*8)(2)+u equation: 



3*2-2*3+u=(3*3-3*8)(2)+u

We move all terms to the left:

3*2-2*3+u-((3*3-3*8)(2)+u)=0

We add all the numbers together, and all the variables

u-((-15)2+u)+3*2-2*3=0

We add all the numbers together, and all the variables

u-((-15)2+u)=0



We calculate terms in parentheses: -((-15)2+u), so:

(-15)2+u

determiningTheFunctionDomain
u+(-15)2

We add all the numbers together, and all the variables

u-30

Back to the equation:

-(u-30)



We get rid of parentheses

u-u+30=0

We add all the numbers together, and all the variables

30!=0

There is no solution for this equation

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