3*m*m+7=9

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Solution for 3*m*m+7=9 equation:



3m*m+7=9
We move all terms to the left:
3m*m+7-(9)=0
We add all the numbers together, and all the variables
3m*m-2=0
Wy multiply elements
3m^2-2=0
a = 3; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·3·(-2)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{6}}{2*3}=\frac{0-2\sqrt{6}}{6} =-\frac{2\sqrt{6}}{6} =-\frac{\sqrt{6}}{3} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{6}}{2*3}=\frac{0+2\sqrt{6}}{6} =\frac{2\sqrt{6}}{6} =\frac{\sqrt{6}}{3} $

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