3*sin(2*x)+cos(2*x)+3=0

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Solution for 3*sin(2*x)+cos(2*x)+3=0 equation:


Simplifying
3sin(2x) + cos(2x) + 3 = 0

Remove parenthesis around (2x)
3ins * 2x + cos(2x) + 3 = 0

Reorder the terms for easier multiplication:
3 * 2ins * x + cos(2x) + 3 = 0

Multiply 3 * 2
6ins * x + cos(2x) + 3 = 0

Multiply ins * x
6insx + cos(2x) + 3 = 0

Remove parenthesis around (2x)
6insx + cos * 2x + 3 = 0

Reorder the terms for easier multiplication:
6insx + 2cos * x + 3 = 0

Multiply cos * x
6insx + 2cosx + 3 = 0

Reorder the terms:
3 + 2cosx + 6insx = 0

Solving
3 + 2cosx + 6insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 2cosx + -3 + 6insx = 0 + -3

Reorder the terms:
3 + -3 + 2cosx + 6insx = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2cosx + 6insx = 0 + -3
2cosx + 6insx = 0 + -3

Combine like terms: 0 + -3 = -3
2cosx + 6insx = -3

Add '-6insx' to each side of the equation.
2cosx + 6insx + -6insx = -3 + -6insx

Combine like terms: 6insx + -6insx = 0
2cosx + 0 = -3 + -6insx
2cosx = -3 + -6insx

Divide each side by '2osx'.
c = -1.5o-1s-1x-1 + -3ino-1

Simplifying
c = -1.5o-1s-1x-1 + -3ino-1

Reorder the terms:
c = -3ino-1 + -1.5o-1s-1x-1

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