3+((1/2)x)+100=160

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Solution for 3+((1/2)x)+100=160 equation: 



3+((1/2)x)+100=160

We move all terms to the left:

3+((1/2)x)+100-(160)=0



Domain of the equation: 2)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

((+1/2)x)+3+100-160=0

We add all the numbers together, and all the variables

((+1/2)x)-57=0

We multiply all the terms by the denominator


((+1-57*2)x)=0



We calculate terms in parentheses: +((+1-57*2)x), so:

(+1-57*2)x

We add all the numbers together, and all the variables

(-113)x

We multiply parentheses

-113x

Back to the equation:

+(-113x)



We get rid of parentheses

-113x=0

x=0/-113

x=0

Równanie nie ma rozwiązania

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