3+((1/2)x)+100=160

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Solution for 3+((1/2)x)+100=160 equation:



3+((1/2)x)+100=160
We move all terms to the left:
3+((1/2)x)+100-(160)=0
Domain of the equation: 2)x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
((+1/2)x)+3+100-160=0
We add all the numbers together, and all the variables
((+1/2)x)-57=0
We multiply all the terms by the denominator
((+1-57*2)x)=0
We calculate terms in parentheses: +((+1-57*2)x), so:
(+1-57*2)x
We add all the numbers together, and all the variables
(-113)x
We multiply parentheses
-113x
Back to the equation:
+(-113x)
We get rid of parentheses
-113x=0
x=0/-113
x=0
Równanie nie ma rozwiązania

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