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3+(1/3x)=(1/6)
We move all terms to the left:
3+(1/3x)-((1/6))=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/3x)+3-((+1/6))=0
We get rid of parentheses
1/3x+3-((+1/6))=0
We calculate fractions
()/18x^2+(-((+1*3x)/18x^2+3=0
We calculate fractions
We do not support expression: x^4
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